CH 431/Lecture 9
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Contents |
LECTURE 9
| CH 431 |
|---|
| Lecture 1 |
| Lecture 2 |
| Lecture 3 |
| Lecture 4 |
| Lecture 5 |
| Lecture 6 |
| Lecture 7 |
| Lecture 8 |
| Lecture 9 |
| Lecture 10 |
| Lecture 11 |
| Lecture 12 |
| Lecture 13 |
| Lecture 14 |
| Lecture 15 |
| Lecture 16 |
| Lecture 17 |
One item that is left on our wish list
Above we have answered the question: what is entropy really, but we still do not have a general criterium for spontaneity, just one that works in an isolated system. Let's fix that now. It leads to two new state functions that prove to be most useful ones of thermodynamics.
Helmholtz energies
| S&McQ 881-2 |
As we saw above, the expression
- dU = TdS -PdV
was only valid for reversible changes.
Let us consider a spontaneous change. If we assume constant volume, the work term drops out. From the Clausius inequality dS>δq/T we get:
- dU≤ TdS (V constant)
- dU-TdS≤0 (V constant)
Consider a new state function
- A ≡ U -TS
- dA = dU -TdS - SdT
If we also set T constant we see that the above expression becomes:
- dA=dU-TdS≤0 (V,T constant)
This means that the Helmholtz energy A is a decreasing quantity for spontaneous processes (regardless of isolation!) and A becomes constant once a reversible equilibrium is reached.
What A stands for
| S&McQ 883 |
A good example is the case of the mixing of two gases. Let's assume isothermal conditions and keep the total volume constant.
For this process the ΔU is zero (isothermal, ideal) but the ΔSmolar = -y1Rlny1-y2Rlny2.
This means that ΔAmolar = RT [y1lny1+y2lny2].
This is a negative quantity because the mole ratios are smaller than unity. So yes this spontaneous process has a negative ΔA.
If we look at ΔA = ΔU - TΔS we should see that the latter term is the same thing as -qrev So we have :
- ΔA = ΔU - qrev = wrev
This is however the maximal work that a system is able to produce and so the Helmholtz energy is a direct measure of how much work one can get out of a system. A is therefore often called the Helmholtz free energy.
Interestingly this work can not be volume work as volume is constant. so it stands for the maximal other work (e.g. electrical work) that can be obtained under the unlikely condition that volume is constant.
Natural variables of A
| S&McQ 888 896 |
Because A≡ U-TS we can write
- dA = dU -TdS -SdT
- dA = TdS -PdV -TdS -SdT = -PdV - SdT
The natural variables of A are volume V and temperature T.
Gibbs energy
| S&McQ 884 781 |
The Helmholtz energy A is developed for isochoric changes and as we have often said before it is much easier to deal with isobaric ones where P= constant. We can therefore repeat the above treatment for the enthalpy and introduce another state function the Gibbs (free) energy
- G≡ H -TS = U + PV - TS = A + PV
If we take both T and P constant (pleasantly achievable conditions!) we get
- dU-TdS + PdV≤0
- dG≤0
G either decreases (spontaneously) or is constant (at equilibrium).
Calculating the state function between two end points we get:
- ΔG = ΔH - TΔS ≤ 0 (T,P constant)
This quantity is key to the question of spontaneity under the conditions we usually work under. If for a process ΔG is positive it does not occur spontaneous and can only be made to occur if it is 'pumped', i.e. coupled with a process that has a negative ΔG. The latter is spontaneous.
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If ΔG=0 we are at equilibrium. |
Phase transitions
| S&McQ cf. 857 |
A phase transition like melting is often done under equilibrium conditions. We have seen that both the H and the S curves undergo a dicontinuity at such a temperature, because there is an enthalpy of fusion to overcome. For a general phase transition at equilibrium at constant T and P, we can say that:
- ΔtrsG = ΔtrsH - TtrsΔtrsS = 0
- ΔtrsH = TtrsΔtrsS
- ΔtrsH / Ttrs=ΔtrsS
For melting of a crystalline solid, we now see why there is a sudden jump in enthalpy. The reason is that the solid has a much more ordered structure than the melt. The decrease in order implies a finite ΔtrsS.
We should stress at this point that we are talking about first order transitions here. The reason for this terminology is that the discontinuity is in a function like S, that is a first order derivative of G (or A). Second order derivatives (e.g. the heat capacity) will display a singularity (+∞) at the transition point.
Direction of the spontaneous change
| S&McQ 885 |
Because the ΔS term contains the temperature T as coefficient the spontaneous direction of a process, e.g. a chemical reaction can change with temperature depending on the values of the enthalpy and the entropy change ΔH and ΔS.
This is true for the melting process, e.g. for water below 0oC we get water=>ice, above this temperature ice melts to water, but it also goes for chemical reactions.
- Take: NH3(g) + HCl(g) => NH4Cl(s)
ΔrH at 298K / 1 bar is -176.2 kJ. The change in entropy is -0.285 kJ/K so that at 298K ΔG is -91.21 kJ. Clearly this is a reaction that will proceed to the depletion of whatever is the limiting reagent on the left.
However at 618K this is a different story. Above this temperature ΔG is positive! (assuming enthalpy and entropy have remained the same, which is almost but not completely true) The reaction will not proceed. Instead the reverse reaction would proceed spontaneously. The salt on the right would decompose in the two gases -base and acid- on the left.
Meaning of the ΔG term
As we have seen, ΔA can be related to the maximal amount of work that a system can perform at constant V and T. We can hold an analogous argument for ΔG except that V is not constant so that we have to consider volume work (zero at constant volume) .
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ΔG stands for the (maximal) reversible, isobaric isothermal non-PV work that a certain spontaneous change can perform. |
The volume work may not be zero, but is corrected for. |
| S&McQ 886 |
- dG = d(U+PV-TS) = dU -TdS - SdT - PdV +VdP
As dU = TdS + δwrev
- dG = δwrev -SdT + VdP + PdV
As the later term is -δwvolume
- dG = δwrev -SdT + VdP - δwvolume
At constant T and P the two middle terms drop out
- dG = δwrev - δwvolume = δwother useful work
Conjugate variables
| S&McQ none |
As discussed before there are many other forms of work possible, such as electrical work, magnetic work or elastic work. Although Simon and McQuarri do not discuss this they are commonly incorporated in the formulism of thermodynamics by adding other terms, e.g:
- dG = -SdT + VdP + ℰde + MdH + FdL + γdA
- ℰde stands for the electromotoric force ℰ and de the amount of charge transported against it.
- MdH stand for magnetization and (change in) magnetic field.
- F stands for the elastic force of e.g. a rubber band dL for the length it is stretched
- γ stands for the surface tension (e.g. of a soap bubble), A for its surafce area.
The terms always appear in a pair of what is known as conjugate variables. That is even clearer if we write out the state function rather than its differential form:
- G = U + PV -TS + ℰe + MH + FL + γA + etc.
| S&McQ 937 |
The PV term can also be generalized -and needs to be so- for a viscous fluid to a stress-strain conjugate pair. It then involves a stress tensor.
We will soon encounter another conjugate pair: μdn that deals with changes in composition (n) and the thermodynamic potential μ
Natural variables of G
Because G ≡ H-TS we can write
- dG = dH -TdS -SdT
- dG = TdS +VdP -TdS -SdT = VdP - SdT
The natural variables of G are pressure P and temperature T. This is what makes this function the most useful of the four U,H,A and G: these are the natural variables of most of your experiments!
| S&McQ 886 899 |
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We now have developed the basic set of concepts and functions that together form the framework of thermodynamics. Let's summarize four very basic state functions:
Note:
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We are now ready to begin applying thermodynamics to a number of very diverse situations, but we will first develop some useful partial differential machinery.